Question

A conductor carrying constant current i is bent in the form of concentric semicircles

Answer 1

Answer:

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· A conductor is bent in the form of concentric semicircles as shown in the figure. The magnetic field at the point 'o' is.

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Answer 2

Answer:

The magnetic field at the centre O will be μ₀i/6a.

Explanation:

Let the magnetic field at point O be B.

B = μ₀i/4a (1 - $\frac{1}{2}$ + $\frac{1}{4}$ - $\frac{1}{8}$ + $\frac{1}{16}$ - $\frac{1}{32}$ ---)

= μ₀i/4a ($\frac{1}{1 - r}$)      ∵ r = -$\frac{1}{2}$

= μ₀i/4a × $\frac{1}{3}$/2

B = μ₀i/6a

The above problem is solved based on the moving charges and magnetism learning.

Magnetism is a result of flowing or moving charges. Magnetic fields further exert pressure on the flow of charge, which in turn exerts a force on other magnets, according to moving Charges and Magnetism. Because there are persistent moving charges present, this phenomenon occurs. Moving charges experience a force from the magnetic field. The direction of the force applied to a moving charge stays perpendicular to the formed plane, which is indicated by the letters "v" and "B," respectively. In this instance, the "Right-Hand Rule" is applied. Additionally, the magnitude of the force is directly proportional to the sine of the angle between "B" and "v."

Thus, the magnetic field intensity is another name for magnetic field strength. It contains a part of the magnetic field produced by an external current.