Question

a conductor has 500 less electron find the magnitude and nature of charge​

Answer 1

Answer:

$8 \times {10}^{ - 17} c$

Explanation:

Charge Q=ne

n is the no. of electrons

e is the electronic charge

So,

$q = 500 \times 1.6 \times {10}^{ - 19}$

$q = 8 \times {10}^{ - 17} c$

Since it has less 500 electrons, the charge will be

$+ 8 \times {10}^{ - 17} coulumb$

Answer 2

Answer:

positive charge because it have deficiency of electron.

Q= +- ne

=500×1.6×10^-19

=500×1.6×10^-19+2

=1.6×10^17 coloumb