A conductor has a negative charge of 11.2 - 10^-19 coulomb. How many electrons are in
excess or shorter than normal state ?
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The quantum of charge is electronic charge e.q=11.2×10−19 Ce=1.6×10−19 CWe know that q=nen=qen=11.2×10−191.6×10−19=7As conductor has positive charge, therefore there is a deficiency of 7 electrons.
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