Question

A conductor has a negative charge of 4.8×10^-17 coulomb. How many electrons are there in excess on it as compared to neutral state?

Answer 1

Given,

q =  $\bold{\mathff{4.8 \times 10^{-17} C}}$

charge of an electron =  $\bold{\mathff{1.6 \times 10^{-19}C}}$

Let n be the number of electrons

According to quantisation of charge,

q = ne [where e is base charge of an electron]

n =?

⇒ n = q/e

or, n =  $\bold{\mathff{\dfrac{4.8 \times 10^{-17}C}{1.6 \times 10^{-19}C}=300e^{-}}}$

or, n = 300

Therefore, 300 excess electron are present.