a conductor has resistance of 15 Omega at hundred degree Celsius and 18 Omega at 400 degree Celsius find the temperature coefficient of the resistance of the material
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Given,Resistance of platinum wire at 0° C, R0=10 ΩResistance of platrinum wire at 273° C, Rt=20 ΩNow, temperaure coefficient α is given byα=Rt2-Rt1Rt1t2-t1⇒α=20-1010273-0=1273⇒α=3.6×10-3 °C-1
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