A conductor having positive charge of 1.12 {10^-18} coulomb how many electrons excess or less on it
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Answered by
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The conductor will have less electrons from its neutralised state because it has positive charge.
The positive charge on conductor=charge on an electron×Number of electrons removed
so...
1.12×10^-18C =1.6×10^-19×n
or
11.2×10^-19=1.6×10^-19n
n=11.2/1.6
n=7 electrons
The positive charge on conductor=charge on an electron×Number of electrons removed
so...
1.12×10^-18C =1.6×10^-19×n
or
11.2×10^-19=1.6×10^-19n
n=11.2/1.6
n=7 electrons
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Explanation:
A conductor having positive charge of 1.12 {10^-18} coulomb how many electrons excess or less on it
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