Question

A conductor o length l is placed perpendicular to a horizontal uniform magnetic

Answer 1

Answer:

Explanation:

Given A conductor of length l is placed perpendicular to a horizontal uniform magnetic field B. Suddenly a certain amount of charge is passed through it, when it is found to jump to a height h. The amount of charge that passes through the conductor is

We need to find the amount of charge that passes through the conductor.

 We know that linear impulse = mv

      F Δ t = m √2 g h

      Also i l B Δ t = μ√2gh

       But i Δ t = Δ q

Therefore (Δ q) (l B) = m√2gh

       So Δ q = m √2gh / B l