A conductor of 2 metre length lies along z axis with a current of 10 amphere in a-z direction. If the magnetic field is equal to B vector is equal to 0.05 ax tesla. Find the force on the conductor.
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Answer:
Magnetic field induction at point P due to current carrying wire is
B
2
=
2πr
μ
0
i
.
2π×0.02
4π×10
−7
×30
B
2
=3×10
−4
T
The direction of B
2
will be perpendicular to B
1
then, the magnitude of the resultant magnetic induction
B=
B
1
2
+B
2
2
=
(4)
2
+(3)
2
×10
−4
=5×10
−4
please mark as brainlest answer
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