Question

A conductor of 3 m in length is moving perpendicularly to magnetic field of 10⁻³ tesla with the speed of 10²m / s , then the e.m.f. produced across the ends of conductor will be(a) 0.03 volt(b) 0.3 volt(c) 3×10⁻³ volt(d) 3 volt

Answer 1

answer : option (b) 0.3 volts

explanation : length of conductor , l = 3m

magnetic field , B = 10^-3 T

speed of conductor , v = 10² m/s

we have to find induced emf

use formula, $\xi=-Blv$

= -10^-3 × 3 × 10² = -0.3 volts

hence, magnitude of emf produced across the ends of conductor will be 0.3 volts .

hence, option (b) is correct.