Physics, asked by jiyanazeer80, 11 months ago

A conductor of 512 resistance has length 2 m and area of cross
section 2 m². If so, find out the resistivity of the material of
the conductor.

Answers

Answered by Anonymous

1

R=512 ohm

l=2m

A=2m²

R=rho*l/A

512=rho*2/2

therefore, rho(resistivity)=512

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