Question

A conductor of a length 10 cm and carrying a current of 1.5a is kept in a magnetic field of 4x10^-4t normal to it the force experienced by it is

Answer 1

Explanation:

To find Lorentz Force,

F=BILsinø

B=4×10-⁴

I=1.5A or 15/10A

L=10cm or 1/10 m

ø=90⁰

so

F=4×10-⁴×(15/10)×(1/10)×sin90

F=60×10-⁶

F=6×10-⁵N