Question

A conductor of capacity 20 mF is charged to 1000 V. The potential energy of the conductor will be

Answer 1

Solution :-

Charge: Q = CV where C is the capacitance in Farads, V is the voltage across the capacitor in Volts and Q is the charge measured in coulombs (C).

So,

V = 1000 V

C = 20 mF = 20 × 10^(-3) F

then,

Q = 20 × [10^(-3) ] × 1000

**** Q = 20 Coulombs

Energy stored:

W = ½ QV = ½ CV2

( where W is the energy measured in Joules.)

Now putting the values,

W = 1/2 { 20 × 1000}

W = 1/2 [ 20000]

W= 10000 Joules Answer

Answer 2

Answer: 10^4 J

Explanation: