A conductor of capacity 20 mF is charged to 1000 V. The potential energy of the conductor will be
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1) 10 kilojoules.
We know that energy stored in a capacitor = cV²/2
Given that
Capacitance = 20 mF = 20 x 10⁻³
Voltage, V = 1000 v
Hence ,
energy = cV²/2
= 20 x 10⁻³ x 1000² / 2
= 10⁴ j
= 10 kj
Hence the energy stored in the capacitor will be 10 kilojoules.
We know that energy stored in a capacitor = cV²/2
Given that
Capacitance = 20 mF = 20 x 10⁻³
Voltage, V = 1000 v
Hence ,
energy = cV²/2
= 20 x 10⁻³ x 1000² / 2
= 10⁴ j
= 10 kj
Hence the energy stored in the capacitor will be 10 kilojoules.
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