Question

a conductor of capacity 20mf is charged to 1000v the potential 3nergy of the conductor will be

Answer 1

Answer:

As per the formula of the energy stored in a capacitor = cV²/2. Given that value of the Capacitance = 20 mF = 20 x 10⁻³, then provide the value of Voltage, V = 1000 v. therefore apply the value and get energy = cV²/2, = 20 x 10⁻³ x 1000² / 2 ,= 10⁴ j = 10 kj. Hope it is right answer.

Answer 2

Explanation:

Energy = $\huge \tt {10}^{4} j = 10 \: kj$