A conductor of length 1.3m placed in a magnetic field of 0.4T. Length of conductor makes an angle 45° with the direction of magnetic field, it will experience a force of 2N. Calculate current in the conductor.
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Let B be uniform magnetic field ,current in the wire of length L be I, then force due to magnetic field is given by
F=ILxB.
L=0.5m
I=1.2 A
B=2T
Therefore,
|F|=(1.2)(0.5)(2)(sin pi/2)=1.2N. In the direction perpendicular to the plane formed by LandB according to right hand screw law for cross product of two vectors.
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