Question

A conductor of length 1 m carrying current of 1 A is placed parallel to a magnetic field of 1 guess. The magnetic force acting on the conductor is: A) Zero C) 10-4 newton B) 1 newton D) 1 dyne​

Answer 1

$\huge \underline{\bf{Answer :- }}$

It is given that,

Length, l=1m

Current, I=1A

Magnetic field,

$B = 1oersted = {10}^{ - 4} kg / {As}^{2}$

Magnetic force,

F=I(L×B)F=1(1×10^−4 sin45)

$f = \frac{ {10}^{4} }{ \sqrt{2} }$

Answer 2

Given :

• Length of the conductor (l) = 1m
• Magnetic Field = 1 gauss = 10⁴ T
• Magnitude of Current (I) = 1 A

To Find :

• The magnetic force acting on the conductor.

We know that :

Magnetic Force on a current carrying conductor is given by,

➻ F = I(L × B)

Here, the conductor is placed parallel to magnetic field.

$\implies \sf \alpha = 0 \\ \: \: \: \: \implies \: \sin( \alpha ) = 0$

Therefore :

$\begin{gathered} \implies \: F = 1 \times 1 \times 1 \times 0 \\ \\ \implies \: F =0 \: N\end{gathered}$

Option (A) is the answer.

∴ The magnetic force of the conductor is Zero.

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