Question

A conductor of length 1m falls freely under gravity from a height of 10m so that it cuts lines of force of horizontal component of earth's magnetic field of strength 3÷100000 wb/m2 find the emf induced in the conductor

Answer 1

1. Question⇒   A conductor of length 1m falls freely under gravity from a height of 10m so that it cuts lines of force of horizontal component of earth's magnetic field of strength 3÷100000 wb/m2 find the emf induced in the conductor?

Explanation:

Answer 2

Answer: Emf induced in the conductor is $0.42mv$.

Explanation-Given-Height$=10m$

Magnetic field strength $=\frac{3}{100000}vm^2$

Find-The emf induced in the conductor.

Solution-Height =$(\frac{velocity}{2g} )^2$

$v^2=10\times 2 \times \frac{9.8}{10}$

$v^2=196$

$v=114m/s$

$E=Blv$

$=3\times 10^{-5} \times 1\times 14$

$=42\times 10^{-5}$

$=0.42mv$

Emf induced in the conductor is $0.42mv$

#SPJ2