Question

A conductor of length 20 cm carrying a current of
5 A is placed in uniform magnetic induction of 4T
making an angle of 30' with the direction of the
field. Find the force acting on the conductor.​

Answer 1

Answer:2N

Explanation:

F= I×B×L×sinTheta

So,

According to the question,

I= 5A

L= 20cm = 20/100m = 0.2m

B= 4T

Theta= 30°

Hence,

F = 5A × 4T × 0.2m × Sin30°

F = 5A × 4T × 0.2m × 1/2 ( sin30° = 1/2)

F = 10A•T × 0.2m

F = 2A•T•m

F = 2N