Question

a conductor of length 25 cm is inclined at an angle 30 degree to a uniform field of magnetic induction 2 T. if a charge of 1 C passes through it in 5 s, calculate the force experienced by the conductor. ​

Answer 1

Answer:The force experienced by the conductor is 0.05 N.

Explanation:

Given that,

Length l = 25 cm

Angle $\theta = 30^{0}$

Magnetic induction B = 2 T

We know that,

The current is

$I = \dfrac{q}{t}$

$I = \dfrac{1\ C}{5\ s}$

$I = 0.2 A$

The force is

$F = BIlsin\theta$

$F = 2\times 0.2 \times 25 \times10^{-2}\times sin 30^{0}$

$F = 2\times 0.2 \times 25 \times10^{-2}\times\dfrac{1}{2}$

$F = 5 .0\times10^{-2} N$

$F = 0.05 N$

Hence, The force experienced by the conductor is 0.05 N.