Question

A conductor of length 50 cm carrying a current of 0.8 A is placed in a magnetic field of intensity 3N/A.m Find the force on the conductor. (1) When the conductor is placed at 30degre in the field. (2) The maximum and minimum force.

Answer 1

Hii here is ur solution


(1) F = BIL . sin theata


F = 3 * 0.8 * 0.5 * 1/2

= 3*0.8*0.5*1/2


F = 0.6 N


(2) F maximum = BIL sin theata

= 3*0.8*0.5*sine90

Force maximum = 1.2N



Force minimum = BIL sin theata

Force minimum = 0 ( theata = 0 )



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