Question

A conductor rod of length (l) is moving
with velocity (v) in a direction normal
to a uniform magnetic field (B). What
will be the magnitude of induced emf
produced between the ends of the moving
conductor?

Answer 1

Answer:

Blv

Explanation:

by Faraday law

d@/dt=E

( here E is emf produced and @ is phie ie is flux)

but d@ = B.A

where B is magnetic field and A is area covered by rod

therefore

B.A/dt=E

let L be the length of rod and dx be the displacement covered by rod

therefore

A=dx*l

E=Bldx/dt

but dx/dt = velocity (v)

so

E = BLV

d