Question

A Conductor whose length is 10 m
and area is 1m², its area is increased
five times, its length is increased
One times, its row is equal to 1 ohm m
its old resistance is 10 ohm. Find its
new resistance?​

Answer 1

Answer:

The resistance of the wire is expressed as R=

A

ρL

where,

rho is the resistivity of the wire,

L is the length of the wire,

A is the area of coss section of the wire.

It is given that the radius of the wire is 1 mm, that is 0.001 m. Therefore the area of cross section is given as πr

2

=3.14×0.001

2

=3.14×10

−6

.

Hence, the resistance of the wire when the resistance is 1 ohm, radius is 1mm, that is 0.001m and resistivity is 1.7\times { 10 }^{ -8 }\quad ohm-meter is expressed as 1=

3.14×10

−6

1.7×10

−8

×L

.

So the length L is derived as follows,

L=

1.7×10

−8

1×3.14×10

−6

=

1.7×10

−8

3.14×10

−6

=1.847×10

−2

.

Hence, the length of the wire is 184.7 meters.