A conductor with rectangular cross section has dimensions (a × 2a × 4a) as shown in figure. Resistance across AB is x, across CD is y and across EF is z.
Answers
Answer:
x > z > y
Explanation:
A conductor with rectangular cross section has dimensions (a × 2a × 4a) as shown in figure. Resistance across AB is x, across CD is y and across EF is z
Resistance R = ρ L/A
ρ = Resistivity
L = Length
A = cross sectional Area
for Resistance between A & B
L = 4a
A = a * 2a
x = ρ 4a /(a * 2a ) = 2ρ/a = 2 (ρ/a)
for Resistance between C & D
L = a
A = 2a * 4a
y = ρ a /(2a * 4a ) = ρ/8a = (1/8)(ρ/a)
for Resistance between E & F
L = 2a
A = a * 4a
z = ρ 2a /(a * 4a ) = ρ/2a = (1/2)(ρ/a)
x > z > y
Answer:
Explanation:A conductor with rectangular cross section has dimensions (a × 2a × 4a) as shown in figure. Resistance across AB is x, across CD is y and across EF is z
Resistance R = ρ L/A
ρ = Resistivity
L = Length
A = cross sectional Area
for Resistance between A & B
L = 4a
A = a * 2a
x = ρ 4a /(a * 2a ) = 2ρ/a = 2 (ρ/a)
for Resistance between C & D
L = a
A = 2a * 4a
y = ρ a /(2a * 4a ) = ρ/8a = (1/8)(ρ/a)
for Resistance between E & F
L = 2a
A = a * 4a
z = ρ 2a /(a * 4a ) = ρ/2a = (1/2)(ρ/a)
x > z > y
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