a cone has a base 3 cm and height 4 cm the uper part of cone is cut in such way that conical piece have a height 1 cm base radius 0.75 cm find the volume of remaining portion
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Given Height of the cylinder (H) = 14 cm
Diameter of the base of cylinder = 7 cm
radius of the base of cylinder (R)= 7/2 cm
Surface area of cylinder = 2πR(R+H)
= 2x (22/7)x(7/2)(7/2 + 14)
= 2 x 11x (35/2)
= 385 cm2
Now Radius of base of cone (r) = 3 cm
height of cone (h) = 4 cm
Surface area of cone = πr(r + √(h2 + r2))
= (22/7)x3x(3 + √(42 + 32) )
= (22/7)x3x(3 + 5)
= (22x3x8)/ 7
= 528 / 7
= 75.43 cm2
Hence the surface area of the remaining solid = Surface area of cylinder – Surface area of 2 cones
= 385 cm2 – 2x75.43 cm2
= 385 cm2 – 150.86 cm2
= 234.14 cm2
Diameter of the base of cylinder = 7 cm
radius of the base of cylinder (R)= 7/2 cm
Surface area of cylinder = 2πR(R+H)
= 2x (22/7)x(7/2)(7/2 + 14)
= 2 x 11x (35/2)
= 385 cm2
Now Radius of base of cone (r) = 3 cm
height of cone (h) = 4 cm
Surface area of cone = πr(r + √(h2 + r2))
= (22/7)x3x(3 + √(42 + 32) )
= (22/7)x3x(3 + 5)
= (22x3x8)/ 7
= 528 / 7
= 75.43 cm2
Hence the surface area of the remaining solid = Surface area of cylinder – Surface area of 2 cones
= 385 cm2 – 2x75.43 cm2
= 385 cm2 – 150.86 cm2
= 234.14 cm2
sahil4071:
sorry brp wrong ans
and mine answer
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the remaining volume of the cone is 34.77 cm^3...
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