A cone has base radius r cm and a fixed height 18 cm.The radius of the base is increasing at a rate of 0.1 cm s-1.Find the rate of change of the volume when r = 10.
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Answer:
answer is 54pie cm^2 /min
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Answer:
Step-by-step explanation:
v=1/3pier²
dv/dr=2/3pierh
when r=10,dv/dr=2/3pie(10)=20/3pieh
when h=18,dv/dr=20/3pie(18)=120pie
dv/dt=dv/dr×dr/dt
=120pie×0.1
=12pie cm²/
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