A cone of base radius 10 cm is divided into two parts by drawing a plane through the midpoint of its Axis parallel to its base compare the volume of the two parts.
Answers
Answered by
2
As the cone is divided into two equal parts by the axis so, AQ = AP/2
with the help of similarity theory,
QD / PC = AQ / AP
so, QD / PC = 1/2
so, rdius of QD = PC/2 = R/2
now,the volume of frustum = 1/3πR²H - 1/3π(R/2)²(H/2)
= 1/3πR²H*7/8
compare the two parts in cone
1st is the volume of small cone and 2nd the volume of frustum
i.e. (1/3π(R/2)²(H/2))/(1/3πR²H*7/8) = (1/8)/(7/8)=1/7
with the help of similarity theory,
QD / PC = AQ / AP
so, QD / PC = 1/2
so, rdius of QD = PC/2 = R/2
now,the volume of frustum = 1/3πR²H - 1/3π(R/2)²(H/2)
= 1/3πR²H*7/8
compare the two parts in cone
1st is the volume of small cone and 2nd the volume of frustum
i.e. (1/3π(R/2)²(H/2))/(1/3πR²H*7/8) = (1/8)/(7/8)=1/7
Attachments:
film:
Thanks muskan
Answered by
0
Answer:
Step-by-step explanation:
I hope it will be help ful for you!
Attachments:
Similar questions