Question

A cone of base radius r and height h is located at a uniform electric field parallel to its base what is electric flux entering the cone

Answer 1

Since the electric field is uniform and parallel to the base of the cone,

Electric flux = Electric Field × Area of triangle

=E×½× h×2R

= EhR

Answer 2

The electric flux entering the cone is Ehr.

Step-by-step explanation:

Given:

A cone of base radius  $=r$

height $=h$

To find:

Find the electric flux entering the cone.

Formula used:

Electric flux Ф $=E.Acos\theta$.

Solution:

The electric field can pass through the curved surface. We get a triangle with a base length twice the radius of the cone's base and a height equal to the cone's height if we imagine the cone in two dimensions.

So,$A=\frac{1}{2} \times(2r)\times h$

$A=Rh$

The area vector of the resulting triangle would point in the same direction as the electric field.

So, $\theta=0^{o}$

Therefore, Ф$=E.Acos\theta$

$=E.(Rh).cos0$

$=EhR$

Hence, the  electric flux entering the cone is $EhR$.

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