Question

A cone of geighr d is cut byba parallel and distance d by 3 from the base. show that the volume of frustum produced is 70.37 percent of the original cone.​

Answer 1

Step-by-step explanation:

Volume of original cone with height h = V = 1/3 πr2h

Height and radius of new cone = 2h/3 and 2r/3

Volume of new cone = 1/3 π(2r/3)2(2h/3) = 8V/27

Volume of frustum = (1 - 8/27) V = 19V/27

Ratio = 8/27 : 19/27 = 8 : 19