A cone of height 2.8 cm has a lateral surface area 23.10 cm^2.what is the radius of the base.please solve it urgently.please .please
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Answered by
1
lateral surface area is given by π R L L = lateral length or lateral height
L² = R² + H² H = height of cone
L² = R² + 2.8² ----- equation 1
23.10 = 3.14 * R * L
R L = 7.353 cm²
L = 7.353 / R
Substitute in equation 1
7.353² /R² = R² + 2.8²
R^4 + 7.84 R² - 54.066 = 0
Δ = 277.73
R² = 4.412
R = 2.1 cm
L = 3.5 cm
L² = R² + H² H = height of cone
L² = R² + 2.8² ----- equation 1
23.10 = 3.14 * R * L
R L = 7.353 cm²
L = 7.353 / R
Substitute in equation 1
7.353² /R² = R² + 2.8²
R^4 + 7.84 R² - 54.066 = 0
Δ = 277.73
R² = 4.412
R = 2.1 cm
L = 3.5 cm
Answered by
0
lateral surface area is given by πrl l = lateral height
l² = r² + h² h = height of cone = 2.8 cm
l = √ (r² + 2.8²) ----- i
23.10 = 3.14 × r × l
rl = 7.353 cm²
l = 7.353 / r
So
7.353/r = √(r² + 2.8²)
7.353² /r² = r² + 2.8²
r⁴ + 7.84r² - 54.066 = 0
solving r
r = 2.1003 cm
l² = r² + h² h = height of cone = 2.8 cm
l = √ (r² + 2.8²) ----- i
23.10 = 3.14 × r × l
rl = 7.353 cm²
l = 7.353 / r
So
7.353/r = √(r² + 2.8²)
7.353² /r² = r² + 2.8²
r⁴ + 7.84r² - 54.066 = 0
solving r
r = 2.1003 cm
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