Question

A cone of height 6 cm and radius of base 4 cm has its top cut off by a plane parallel to the base and 4 cm from it. Find the volume of the remaining frustum​

Answer 1

Answer:

2

Step-by-step explanation:

△OAB∼△OCD [By AA similarity]

OC

OA

=

CD

AB

AB=

12

4×6

=2cm

TSA of frustum =π(R

1

+R

2

)l+π(R

1

2

+R

2

2

)

=π[(R

1

+R

2

)

(R

1

−R

2

)

2

+h

2

+R

1

2

+R

2

2

]

=

7

22

[(6+2)

(6−2)

2

+8

2

+6

2

+2

2

]

=

7

22

[8×4

5

+36+4]

=

7

22

[32×2.236+40]

=350.59cm

2

solution