A cone of height 8m has a curved
surface area of 188.4 m² find
the volume ?
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Given :-
- If a cone of height 8 M has a curved surface area of 188.4 m²
To Find :-
- Radius
- Volume
Solution :-
We know that
l² = r² + h²
l² = r² + (8)²
l² = r² + 64
l = √(r² + 64)
Now,
188.4 = 3.14 × r × √(r² + 64)
188.4/3.14 = r × √(r² + 64)
60 = r × √(r² + 64)
Squaring both side
(60)² = [r × √(r² + 64)]²
3600 = r²(r² + 64)
3600 = r⁴ + 64r²
0 = r⁴ + 64r² - 3600
0 = r⁴ + (100r² - 36r²) - 3600
0 = r⁴ + 100r - 36r² - 3600
0 = (r² + 100)(r² - 36)
Either
r² = -100
or
r² = 36
As length can't be negative
r² = 36
r = √36
r = 6
Now
Volume of cone = 1/3 × π × r² × h
Volume = 1/3 × 22/7 × (6)² × 8
Volume = 22/21 × 36 × 8
Volume = 22/7 × 12 × 8
Volume = 2112/7
Volume = 301.7 m³
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