Question

A cone of maximum size is carved out from a cube of edge 14cm . FInd out the surface area of the cone and of the remaining solid left out after the carved out . Plzz Answer ....

Answer 1

The cone will have a diameter of 14 cm and height of 14 cm. (Radius = 7cm)

Slant height of cone = √(14² + 7²) = 15.652 cm

Surface area = 22/7 x 7 x 15.652 + 22/7 x 7² = 498.35 cm²
Surface area of solid remaining solid = Total surface area of the cube - area of circle where the cone was carved out + curved surface area of cone (hole remaining in the cube)
= 14x14x6 - 22/7x7² + 22/7x7x15.652
= 1366.344 cm²

Answer 2

Answer:

Step-by-step explanation:

Solution :-

Since, a cone of maximum size is a curved out from a cube

So, radius of cone, r = 14/2 = 7 cm

And height of cone, h = 14 cm

Slant height of cone = √7² + 14² = √245 = 7 √5 cm

Surface area of remaining solid = 6l² - πr² + πrl

Surface area of remaining solid = 6 × 14 × 14 - 22/7 × 7 × 7 + 22/7 × 7 × 7√5

Surface area of remaining solid = 1176 - 154 + 154 √ 5

Surface area of remaining solid = (1022 + 154 √5) cm²

Hence, the remaining solid left out after the carved out is  (1022 + 154 √5) cm².