A cone of maximum size is carved out from a cube of edge 14 cm. Find the surface area
of the remaining solid after the cone is carved out
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Hi there!
Surface area of remaining solid = 6L² - πr² + πrl,
where r and l are the radius and slant height of the cone.
Here,
Diameter of Cone = Edge of Cube = 14 cm
Radius, r = 14/2 = 7 cm
Now,
✨ TSA of Cube:
6(side)²
6 × 14²
6 × 196
1176 cm²
✨ Slant height of Cone:
l = √r² + h²
= √7² + 14²
= √7²(1+2²)
= 7√5 cm
✨ Curved Surface area of Cone:
πrl
22/7 × 7 × 7√5
154√5 cm²
✨ Base area of Cone:
πr²
22/7 × 7 × 7
154 cm²
Therefore,
Surface area of remaining solid = 6L² - πr² + πrl
= 1176 + 154√5 - 154
= 1022 + 154√5
Cheers!
Surface area of remaining solid = 6L² - πr² + πrl,
where r and l are the radius and slant height of the cone.
Here,
Diameter of Cone = Edge of Cube = 14 cm
Radius, r = 14/2 = 7 cm
Now,
✨ TSA of Cube:
6(side)²
6 × 14²
6 × 196
1176 cm²
✨ Slant height of Cone:
l = √r² + h²
= √7² + 14²
= √7²(1+2²)
= 7√5 cm
✨ Curved Surface area of Cone:
πrl
22/7 × 7 × 7√5
154√5 cm²
✨ Base area of Cone:
πr²
22/7 × 7 × 7
154 cm²
Therefore,
Surface area of remaining solid = 6L² - πr² + πrl
= 1176 + 154√5 - 154
= 1022 + 154√5
Cheers!
rajveersinghkap3hgb5:
thank u soo much
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