A cone of radius 10 cm is divided into two parts by a plane mirror to its base through the mid point of his height. Compare the volumes of the two parts
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cone will be divided into an another small cone and frustum...
vol of cone= 1÷3 πr^2h
vol of frustum = 1÷3πh(R^2+r^2+R+r)
by comparing we get.....???
vol of cone= 1÷3 πr^2h
vol of frustum = 1÷3πh(R^2+r^2+R+r)
by comparing we get.....???
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