Question

a cone of radius 10 cm is divided into two parts by drawing a plane through the midpoint of its Axis parallel to its base compare the volume of two parts

Answer 1

⛦Hᴇʀᴇ Is Yoᴜʀ Aɴsᴡᴇʀ⚑
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➧ In such case the ratio of the volumes of each part can be calculated as follows:

Here, AG = GH = h

➧ And since triangle AGD ~ triangle AHC
(by AAA similarity criterion)

➧ So, (AG/AH) = (GD / HC)
(corresponding sides of similar triangles)

➾ h/ 2h = GD /10

➾ 2GD = 10

➾ GD = 5 cm

➧ So, now, Volume of Cone AED
➾ 1/3 pi r² h

➾ 1/3 pi × 25 × h …………(1)

➧ And Volume of the frustum BCDE Of the Cone = Volm (Cone ABC) — Volm ( ConeAED)

➾ 1/3 × pi × 100 × 2h — 1/3 × pi × 25×h

➾ 1/3* pi* h ( 200 - 25)

➾ 1/3 * pi * h* 175 ………….(2)

➧ So ratio of 2 parts
➾ (1) ÷ (2)

➾ (1/3 × pi × 25 × h) ÷ ( 1/3 × pi × h × 175)

➾ 25 / 175

➾ 1 / 7 ...✔

__________
Thanks...✊

Answer 2

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