Question

a cone of radius 10cm is cut into two parts by a plane through the mid point of its vertical axis parallel to the base find the ration of the volume of the smaller cone to the frustum of the cone​

Answer 1

Answer:

Step-by-step explanation:

As the cone is divided into two equal parts by the axis so, AQ = AP/2

with the help of similarity theory,

QD / PC = AQ / AP

so, QD / PC = 1/2

so, rdius of QD = PC/2 = R/2

now,the volume of frustum = 1/3πR²H - 1/3π(R/2)²(H/2)

                                                = 1/3πR²H*7/8

compare the two parts in cone

1st is the volume of small cone and 2nd the volume of frustum

i.e. (1/3π(R/2)²(H/2))/(1/3πR²H*7/8) = (1/8)/(7/8)=1/7