A cone of radius 12cm and height 20cms is cut parallel to the basefrom the top 3cmsdown and removed put the remaining part becomes the frustum of a cone find the ratio between the frustum of a cone and the cone which is removed out
please answer this fast
Answers
Answered by
1
Answer:
Step-by-step explanation:
\textrm{Volume of cone is given as}V=\frac{1}{3} \pi r^2h
\textrm{Now the volume of cone }=\frac{1}{3} \times\frac{22}{7} \times12^{2} \times20
= 3017.14cm^3
\textrm{Now the height of smaller cone will be calculated as}
\frac{20}{12} =\frac{x}{3} \\
\textrm{after solving this we can get x} =5cm
\textrm {So the volume of smaller cone will be}=\frac{1}{3} \times\frac{22}{7} \times3^{2} \times5
=47.14 cm^3
\textrm {Now volume of frustum of cone is given by} \\=\textrm {Volume of bigger cone -Volume of smaller cone}\\=3017.14 - 47.14\\=\bold{2970 cm^3}
PLZ MARK BRAINLIEST
Step-by-step explanation:
Similar questions