Question

A cone of radius 15 cm and height 18 cm is completely filled with water.this water is emptied into an empty cylindrical vessel of redius 4.5 cm.what will be the height of water in this vessel ?​

Answer 1

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Answer 2

Answer:

answer: - 66.6cm

Step-by-step explanation:

$volume \: of \: water \: in \: cone = \frac{1}{3} \pi {r}^{2} h \\ \\ v = \frac{1}{3} \times \pi \times {(15)}^{2} \times 18 \\ \\ v = 1350\pi \\ \\ let \: the \: height \: of \: cylinder \: be \: x \\ \\ now \\ \\ volume \: of \: water \: in \: cone \: = volume \: of \: water \: in \: cylinder \\ \\ v = \pi {r}^{2} h \\ \\ 1350\pi = \pi \times {(4.5)}^{2} \times x \\ \\ x = \frac{1350\pi}{\pi \times 4.5 \times 4.5} \\ \\ x = 66.6cm$