Question

A cone of radius 8 cm and height 16 centimetre is divided into two parts by plane through the midpoint of its axis parallel to its base find the ratio of their volumes of two parts

Answer 1

Answer:

To find the radius(r)

r/8=8/16r, r = 64/16=4cm

vol. of smaller Cone

I/3πr^2h='/3πx4^2 x8=133.97 cm3

vol. of big cone

1/3πR^2H=1 / 3π8^2 xl6=.IO71.78

Area of frustum

1071.78 -133.97=937.81

Ratio of smaller Cone and frustum

= 931-8l: 133.97=I:7

ANSWERI:7