Question

A cone’s height is reduced to 2004-06-01-04-00_files/i0470000.jpg of its original length, and its radius is tripled. How has the volume of the cone changed? A. The volume is now 2004-06-01-04-00_files/i0470003.jpg of the original size. B. The volume is now 2004-06-01-04-00_files/i0470004.jpg of the original size. C. The volume is now 2004-06-01-04-00_files/i0470002.jpg of the original size. D. The volume is now 2004-06-01-04-00_files/i0470001.jpg of the original size.

Answer 1

HELLO DEAR,

YOUR QUESTIONS IS-------------->A cone’s height is reduced to 3/8 of its original length, and its radius is tripled. How has the volume of the cone changed?


we know volume of cone = (1/3) * πr²h

now,
he changes to (3/9) h and r changes to (3r)

So, V = (1/3) * (3/8)h * π * (3r)²

⇒V = (1/3) * (3/8)h * π * (9r)²

⇒V = {(1/3) * π * r² * h} * (3/8) * 9

⇒V = volume of original cone * (27/8)

HENCE, changes in volume = 27/8 of original volume.

I HOPE ITS HELP YOU,
THANKS