Question

A cone-shaped tent has a diameter of 12 ft and a height of 6 ft. What is the approximate volume of the tent? Use 3.14 to approximate pi, and express your final answer as a decimal. Enter your answer in the box. ft³

Answer 1

the ans is 226.08 ft^3

Answer 2

Given:

Diameter of the cone-shaped tent = 12 ft

Height = 6 ft

To find:

Volume of the tent

Solution:

Formula to be used:

$\boxed{Volume\: of\:cone = \frac{1}{3} \:*\: pi\: *\:r^2\:*\:h}$

The diameter = 12 ft

∴ The radius of the cone-shaped tent = $\frac{Diameter}{2}$ = $\frac{12}{2}$ = 6 ft

Now,

We will substitute the given values in the formula of the volume of cone.

∴ Volume of the cone-shaped tent is given by,

= $\frac{1}{3} \:*\: pi *\: 6^2\: *\: 6$

taking the approximate value of pi as 3.14

= $\frac{1}{3} \:*\:3.14\:*\: 36\:*\:6$

= $\frac{678.24}{3}$

= 226.08 ft³

Thus, $\boxed{The\:approximate\:volume\:of\:the\:tent\: is\:226.08\:ft^3 }$

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