A cone with its height equal to the diameter of the base is expanding in volume at the rate of 50 cm®/sec. If the base has area 1 m², the radius is increasing at the rate (A) 0.0025 cm/sec (B) 0.25 cm/sec (C) 1 cm/sec (D) 4 cm/sec
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Correct option is D)
Let the radius of the cone be r
Let base area =A
Volume of cone =V=
3
1
πr
2
h=
3
1
πr
2
d=
3
1
πr
2
(2r)=
3
2
πr
3
dt
dV
=2πr
2
dt
dr
Given,
dt
dV
=40cm
3
/s,A=πr
2
=1m
2
=10000cm
2
⇒40=2(10000)
dt
dr
⇒
dt
dr
=0.0025
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