Math, asked by sneha622, 1 year ago

a confectioner had some boxes for burger and he bought 50 more boxes. After two days half of these boxes were used and only 40 boxes were left. Find the no. of boxes he had in the beginning?

Answers

Answered by siddharth052003
52

Answer:

He had 30 boxes in the beginning.

Step-by-step explanation:

Suppose that he had x number of x boxes.

He bought 50 more boxes.

So, total number of boxes = x + 50

After two days, half of these boxes were used and 40 were left.

This means that, x + 50/2 were used and 40 were left.

( x + 50 ) - ( x + 50/2 ) = 40

( 2x + 100 - x - 50) /2 = 40

( x + 50 ) / 2 = 40

x + 50 = 80

x = 30



sneha622: thank you so much
Answered by Simran2302
24

Answer:The confectioner initially had 30 boxes.


Step-by-step explanation:

well,let the confectioner has x no of boxes at first.

now after adding 50 boxes to the initial no of boxes,the confectioner has (x+50)boxes.

it is said half of these boxes were sold and 40 were left, which means (x+50)/2=40

or,x+50=40*2

or,x=80-50

or,x=30

I HOPE THIS HAS HELPED YOU


sneha622: thanks
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