Question

a confectioner had some boxes of burger and he bought 50 more boxes. after two days half of these boxes were used and only 40 boxes were left. find the number of boxes he had in beginning?

Answer 1

Let x be initial no of boxes. Therefore, x+50 now. x+50/2 were used. Now, x+50-x+50/2=40.on solving, the value of x we get is 30.So,ans.=30.

Answer 2

The number of boxes the confectioner had in the beginning is 30.

• Let the number of boxes of burger be x.

• Then the confectioner brought 50 more boxes.

The number of boxes of burger then becomes x+50.

• Now after two days , half the boxes were sold and 40 were left .

Total number of boxes = Half of total boxes + 40

x + 50 = $\frac{x+50}{2}$ + 40

x + 10 = $\frac{x+50}{2}$

2x + 20 = x + 50

x = 30

• The number of boxes h had in the beginning is 30.