Question

A conference hall is 14m long and 8m wide and 4m high there are 4 windows and one door the door measures 1m by 2m and each window measures 1m by 1.5m.

a) How many litres are needed to paint all the walls of the hall if one litre is enough for covering 18m^2.

b) what will be the cost of painting the hall if 1 litre cost rs. 225.

please answer with full explanation​

Answer 1

THIS IS THE REQUIRED SOLUTION TO THE ABOVE QUESTION !

IF ANY MISTAKES IN CALCULATION EXISTS, SURELY LET ME KNOW !

Answer 2

$\bold\green{Answer}$

a)paint required = $\frac{28}{3}$ litres

b)Total cost = 2100 Rs.

$\underline\pink{Explanation}$

$\red{Given}$

• Length of conference hall = 14 m
• Breadth of conference hall = 8m
• Height of conference hall = 4m
• Length of door = 2m
• Breadth of door = 1m
• Length of window = 1.5m
• Breadth of window = 1m

$\rule{300}{2}$

Conference hall is of the shape of cuboid

$\rule{300}{2}$

First, We have to calculate area of four walls-

Lateral surface area of cuboid = 2h(l+b)

= 2×4(14 + 8)

= 176${m}^{2}$

Second, We have to calculate area of door and windows-

$\rule{300}{2}$

Door and windows are of the shape of rectangle.

$\rule{300}{2}$

Area of door = 2×1

=2${m}^{2}$

Area of 1 window = 1.5×1

=1.5${m}^{2}$

$\underbrace{There\:are\:Total\:4\:windows}$

Area of 4 windows = 4×1.5

= 6${m}^{2}$

$\rule{300}{2}$

Area of 4 walls to be painted - area of four walls -(area of door + area of 4 windows)

$\rule{300}{2}$

Area of walls to be painted = 176-(2+6)

= 168 ${m}^{2}$

a)Given that 1 litre is enough for convering 18${m}^{2}$

Total paint required = $\frac{168}{18}$

=$\frac{28}{3}$ litres

b)1 litres cost Rs. 225

$total \: cost = 225 \times \frac{28}{3} \\ = 28 \times 75 \\ = rs. 2100$

$\boxed{Thankyou!}$