Question

A conic passing through origin has its foci at (5, 12) and (24,7). Then its eccentricity is​

Answer 1

Answer:

12386

Given that,

Foci at (5,12) and (24,7)

Then we know that,

Distance between foci in hyperbola =2ae=(24−5)2+(7−12)2=192+(−5)2=386 …….. (1)

Also,

Foci radii=2a=242+72−52+122

=25−13=12 …….. (2)

Divide equation (1) and (2) to,

2a2ae=12386

e=12386

Answer 2

Answer:

12386

Step-by-step explanation:

Hope it helps

Thankyou