A CONICAL CAVITY OF DIAMETER 6 CM AND HEIGHT 4 CM IS REMOVED FROM THE BASE OF A WOODEN CYLINDER OF DIAMETER 12 CM AND HEIGHT 8 CM FIND:-1
VOLUME OF REMAINING SOLID (2) TSA OF REMAINING SOLID
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Answer:
1)height = 8cmdiameter = 6/2=3cm
Step-by-step explanation:
1)volucme remaining solid
2πrh
=2×22/7×4×3
=88/7×12
=1056/7
=150.871(aprox)
2) h=8 diameter=12/2=6
TSA of remaining solid
2πr×(r+h)
=2×22/7×6(6×8)
=2×22/7×6×48
=2×22/7×288
=25344/7
=3620.5714(approx)
I hope the it is help u
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