A conical flask is full of water. The flask has base-radius r and height h. The water is poured into a cylindrical flask of base-radius mr. Find the height of water in the cylindrical flask.
Answers
Answered by
14
Answer:
The height of the water in the cylindrical flask is h/3m²
Step-by-step explanation:
Given:
Base radius of the conical flask = r m
Height of the conical flask = h m
Base radius of the cylindrical flask = mr
Volume of the water in the conical flask = ⅓ πr²h……………..(1)
Let the height of the cylindrical flask be h1.
Volume of the cylindrical flask = πr²h1 = π(mr)²h1 ……….(2)
Since, water in conical flask is poured into cylindrical flask so their volumes are same.
Volume of the water in the conical flask = Volume of the cylindrical flask
⅓ πr²h = π(mr)²h1
⅓ r²h = m²r²h1
1/3h = h1m²
3h1m² = h
h1 = h/3m²
Hence, the height of the water in the cylindrical flask is h/3m² .
HOPE THIS ANSWER WILL HELP YOU….
Answered by
12
Volume of water = Volume of conical flask = 1/3πr²h
Now, the water is poured into cylindrical flask.
Volume of cylinder = Volume of water
= π(mr)²×Height=13πr²h
Height = h/3m²
Hope it helps ✌✌❤
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