Math, asked by BrainlyHelper, 1 year ago

A conical flask is full of water. The flask has base-radius r and height h. The water is poured into a cylindrical flask of base-radius mr. Find the height of water in the cylindrical flask.

Answers

Answered by nikitasingh79
14

Answer:

The height of the water in the cylindrical flask  is h/3m²

Step-by-step explanation:

Given:

Base radius of the conical flask = r m

Height of the conical flask = h m

Base radius of the cylindrical flask =  mr

Volume of the water in the  conical flask  = ⅓ πr²h……………..(1)

Let the height of the cylindrical flask be h1.

Volume of the cylindrical flask = πr²h1 = π(mr)²h1 ……….(2)

Since, water in conical flask is poured into cylindrical flask so their volumes are same.

Volume of the water in the  conical flask = Volume of the cylindrical flask

⅓ πr²h = π(mr)²h1

⅓ r²h = m²r²h1

1/3h = h1m²

3h1m² = h

h1 = h/3m²

Hence, the height of the water in the cylindrical flask  is h/3m² .

HOPE THIS ANSWER WILL HELP YOU….

Answered by OrangyGirl
12

Volume of water = Volume of conical flask = 1/3πr²h

Now, the water is poured into cylindrical flask.

Volume of cylinder = Volume of water

= π(mr)²×Height=13πr²h

Height = h/3m²

Hope it helps ✌✌❤

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