a conical flask of radius a and height 2a is full of water . if the water is poured into a cylindrical flask of radius 2a/3 then find the height of water in the cylindrical flask
Answers
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>>The height of the water in the cylindrical flask is h/3m²
<<Step-by-step explanation:>>
Given:
Base radius of the conical flask = r m
Height of the conical flask = h m
Base radius of the cylindrical flask = mr
Volume of the water in the conical flask = ⅓ πr²h……………..(1)
Let the height of the cylindrical flask be h1.
Volume of the cylindrical flask = πr²h1 = π(mr)²h1 ……….(2)
Since, water in conical flask is poured into cylindrical flask so their volumes are same.
Volume of the water in the conical flask = Volume of the cylindrical flask
⅓ πr²h = π(mr)²h1
⅓ r²h = m²r²h1
1/3h = h1m²
3h1m² = h
h1 = h/3m²
Hence, the height of the water in the cylindrical flask is h/3m² .
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Answer:
(3a/2) cm
Step-by-step explanation:
Given:
A conical flask of radius a and height 2a is full of water . if the water is poured into a cylindrical flask of radius 2a/3.
To Find:
Find the height of water in the cylindrical flask.
Solution:
Volume of water in the conical flask will be equal to the volume of water in the cylindrical flask.
Volume of a cylinder = πR²h
Volume of a cone = 1/3 πr²h
The water is poured into a cylindrical flask of base-radius 2a/3.
πR²h = 1/3 πr²h
⇒ (2a/3)² * h = (1/3) * a² * 2a
⇒ h = (3a/2) cm
Result:
height of water in the cylindrical flask = (3a/2) cm