Question

A conical funnel of diameter 23.2 cm and depth 42 cm contains water filled to the brim. The water is poured into a cylindrical tin of diameter 16.2 cm. If the tin must contain all the water, find its least possible height.​

Answer 1

Answer:

first follow me and mark as a brainlist answer

then I will give the answer

Answer 2

GIVEN :-

• Diameter of the conical funnel = 23.2 cm

        ∴ Radius of the conical funnel ( $\sf r_1$ ) = 11.6 cm

• Depth/height of the cone ( $\sf h_1$ ) = 42 cm

• Diameter of the cylinder = 16.2 cm

        ∴ Radius of the cylinder ( $\sf r_2$ ) = 8.1 cm

TO FIND :-

• Height of the cylinder ( $\sf h_2$ ) .

SOLUTION :-

 According to the question,

 Volume of conical funnel = Volume of cylinder

  $\bullet \sf \ Formula \ to \ find \ volume \ o f \ cone = \dfrac{1}{3}\pi r^2h \\\\\bullet Formula \ to \ find \ volume \ of \ cylinder = \pi r^2h$

 $\longrightarrow\sf \dfrac{1}{3}\times \pi \times (r_1)^2\times h_1 = \pi \times (r_2)^2 \times h_2 \\\\\longrightarrow \dfrac{1}{3}\times \pi \times 11.6 \times 11.6 \times 42 = \pi \times 8.1 \times 8.1 \times h_2 \\\\\longrightarrow 11.6\times11.6\times 14 = 8.1\times 8.1 \times h_2 \\\\\longrightarrow 1883.84 = 65.61 \ h_2\\\\\longrightarrow h_2 = \dfrac{1883.84}{65.61} \\\\\longrightarrow \bf h_2= 28.7$

Height of the cylinder = 28.7 cm